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いろいろ (1-x^2)y'' 2xy'=0 200241-X 2 1 y 2xy 2 0

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Log(xy)=2xyOn differentiating both sides wrt x, we get( xy1 )(1 dxdy )=2(x dxdy y)⇒ dxdy = 2x 22xy−11−2xy−2y 2 at x=0,y=1 (from logxy=2xy)Now, at x=0,y′(0)= −11−2 =1 Ex 96, 14 For each of the differential equations given in Exercises 13 to 15 , find a particular solution satisfy the given condition 1 2 2 = 1 1 2 ; This problem has been solved! Misc 7 Show That General Solution Is X Y 1 A 1 X Y 2xy X 2 1 y 2xy 2 0

[10000印刷√] (1/2)^x+(1/2)^x-2 5 166639-1.solve the equation 3(2^(x)+1)-2^(x+2)+5=0

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Solve For X 1 2x 3 1 X 5 10 9 Mathematics Topperlearning Com Fuu29nqq 2 (a) Evaluate each of the following, if itAnswer (1 of 6) Let us Take is (x1)/22/(x1)=(x1)/33/(x1)5/6 I hope ur real number are one site and other site is x by numerical (X1)/2(x1)/35/6=3/(x1)2 1.solve the equation 3(2^(x)+1)-2^(x+2)+5=0