いろいろ (1-x^2)y'' 2xy'=0 200241-X 2 1 y 2xy 2 0
Log(xy)=2xyOn differentiating both sides wrt x, we get( xy1 )(1 dxdy )=2(x dxdy y)⇒ dxdy = 2x 22xy−11−2xy−2y 2 at x=0,y=1 (from logxy=2xy)Now, at x=0,y′(0)= −11−2 =1 Ex 96, 14 For each of the differential equations given in Exercises 13 to 15 , find a particular solution satisfy the given condition 1 2 2 = 1 1 2 ; This problem has been solved! Misc 7 Show That General Solution Is X Y 1 A 1 X Y 2xy X 2 1 y 2xy 2 0